The area of the polygons compare to π in the way that as
more angles and sides are added to a polygon the polygon becomes closer to a
circle; the perimeter slowly changes to circumference. Π is used to find the
area and circumference of a circle, so as polygons come closer to becoming circles
π becomes more strongly associated to the polygon. You can even use π to find
the approximate area of a circle if you use the same formula (as you would to
find the area of a circle) on a polygon. Another way to go about it is like
this…
You can find the area of a circle if you know the circle’s
circumference by using these steps:
<span>1. Divide the
circumference by π to find the diameter of the circle.</span>
<span>2. Divide the
diameter by 2 to find the radius of the circle.</span>
<span>3. Now that you
have the radius you can use the formula Area= πr2 to find the area of the
circle.</span>
A picture can help.
The median to the long side divides the isosceles triangle into two right triangles with hypotenuse 10 and short leg 6. Thus the long leg (median of interest) is found by the Pythagorean theorem to be
... √(10² -6²) = √64 = 8
Then the midpoint of the short side is found to be 6 + (6/2) = 9 units to the side and 8/2 = 4 units above the opposite vertex. Hence the square of the length of that median is 9² + 4² = 97.
The sum of squares of interest is
... 8² + 2×97 = 258
Answer:
19 > DB > 5
Step-by-step explanation:
In a triangle Δ ABC, AC = 7, and BC = 18.
Therefore, the length of the third side of the triangle Δ ABC i.e. length of AB can have a maximum value of < (7 + 18) i.e. 25 and the minimum value of the length AB will be > (18 - 7) i.e. 11
Hence, the length of AB will be given by 25 > AB > 11.
Now, AB = AD + DB = 6 + DB {Since length of AD is given to be 6}
Therefore, 25 > 6 + DB > 11
⇒ 19 > DB > 5 (Answer)
Answer:
Step-by-step explanation:
(-9-7)/(0-1)= -16/-1= 16
y - 7 = 16(x - 1)
y - 7 = 16x - 16
y = 16x - 9
