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iogann1982 [59]

3 years ago

10

José paid $47.00 for 4 movie tickets. Each ticket cost the same amount. What was the cost of each movie ticket in dollars and ce

nts?

1 answer:

Komok [63]3 years ago

3 0

11.75$ you divide 47.00/4 since their are 4 tickets and they are all the same price

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7. William wrote a check for $150.00 for his gas bill, but he only has 96.26 in his checking account. What will happen to the ch

Alex17521 [72]

Answer:

-$53.74

Step-by-step explanation:

96.26 - 150.00 = -53.74

8 0

3 years ago

There are ten cards, each has a different number on it, from 1 to 10. Sam took one card, and it was 5 on it. If he takes one of

Akimi4 [234]

there are 9 cards left

1,2,3,4,6,7,8,9,10

the only cards that will make the sum less than 8 is 1 and 2

2/9

Answer: 2/9

6 0

4 years ago

Read 2 more answers

You can copy the data into Excel by highlighting the data, right-clicking and selecting Copy, then opening Excel, clicking on a

Iteru [2.4K]

Answer:

Low income group :

Mean = 22.100

Median = 22.000

Standard deviation = 4.717

High Income group :

Mean = 19.771

Median = 20.000

Standard deviation = 3.255

Step-by-step explanation:

Low income : 19,20,13,28,21,27,16,21,19, 19,34,24, 24,14,24,25,23,22,20,21,14,23,17,26,24,24,20,24,27,16,22,17,29,20,25,22,20,34,24,22

High Income : 23 19 19 18 20 18 17 25 13 24 25 17 21 19 17 22 22 15 19 23 19 23 22 20 20 20 13 21 16 13 21 24 23 21 20

Using Excel :

Mean of low income, Σx / n = 884/40 = 22.100

Median of low income group : 1/2(n+1)th term = Median of low income = 22.000

Standard deviation of low income group :

√(Σ(x - mean)²/n) = 4.717

High Income group :

Mean of high income, Σx / n = 692/35 = 19.771

Median of high income group : 1/2(n+1)th term = Median of high income = 20.000

Standard deviation of low income group :

√(Σ(x - mean)²/n) = 3.255

5 0

3 years ago

Please help me with this Algebra I question.

horrorfan [7]

Answer:

$-\dfrac{b^2}{16a^4}$

Step-by-step explanation:

Given expression:

$\dfrac{(2a)^{-2}b^5}{-4a^2b^3}$

$\textsf{Apply the exponent rule}\quad (ab)^c=a^c \cdot b^c:$

$\implies \dfrac{2^{-2}a^{-2}b^5}{-4a^2b^3}$

Separate the variables:

$\implies \dfrac{2^{-2}}{-4}\cdot \dfrac{a^{-2}}{a^2}\cdot \dfrac{b^5}{b^3}$

$\textsf{Apply the exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies \dfrac{2^{-2}}{-4}\cdot a^{-2-2}\cdot b^{5-3}$

$\implies \dfrac{2^{-2}}{-4}\cdot a^{-4}\cdot b^{2}$

$\textsf{Apply the exponent rule}\quad a^{-n}=\dfrac{1}{a^n}:$

$\implies \dfrac{1}{-4(2^2)}\cdot \dfrac{1}{a^4}\cdot b^{2}$

$\implies -\dfrac{1}{16}\cdot \dfrac{1}{a^4}\cdot b^{2}$

Simplify:

$\implies -\dfrac{b^2}{16a^4}$

5 0

2 years ago

Round 1.6 to the nearest tenths and 1.64 to the nearest hundredths what was the original number?

Law Incorporation [45]

1.6 is the nearest 10th because the 6 is a tenth .0. and 1.64 to the nearest hundredths would be 1.6 so the original number is 1.6<span />

7 0

4 years ago