To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
Answer:
0.052 acre/min
Step-by-step explanation:
6 1/4 acres / 2 hours times the conversion factor (1 hr / 60 min) comes out to:
6.25
----------------- = 0.052 acre/min
2 (60 min)
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Answer:
The range is from 125 to 133.
Step-by-step explanation:
That's the lowest and highest the weights go, therefore the range is from 125 and anything in between up to 133.
Answer:
$40,000
Step-by-step explanation:
this the workings above
Answer: 2 54
Step-by-step explanation: