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3 years ago

7

Suppose you want to have $800,000 for retirement in 20 years. Your account earns 8% interest. How much would you need to deposit

in the account each month?

1 answer:

natulia [17]3 years ago

7 0

Answer:

$40,000

Step-by-step explanation:

this the workings above

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What is -5.8+(-2.5)

Scilla [17]

-5.8 + (-2.5) = -8.3

since both the number are negative you simply add the numbers and use the negative sign.

5 0

3 years ago

So I’m not smart so like help meh pleasee<br><br> What is 49% of 200?

____ [38]

Answer:98

Step-by-step explanation:

We assume, that the number 200 is 100%.if 200 is 100%, so we can write it down as 200=100%.We also know, that x is 49% of the output value, so we can write it down as x=49%.Now we have two simple equations:

1) 200=100%

2) x=49%

we multiply both sides of the equation by x.then we divide both sides of the equation.

3 0

3 years ago

Landon is building new bookshelves for his bookstore's new mystery section. Each shelf can hold 38

Novosadov [1.4K]

Answer:

33

Step-by-step explanation:

1254 divided by 38 is 33

7 0

3 years ago

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Whats the answer, to the question below

NISA [10]

The answer to this problem is 5.

6 0

3 years ago

Read 2 more answers

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

a)

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

b)

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

c)

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago