All categories

3 years ago

A car is traveling at an initial velocity of 23m/s. It begins to accelerate at a rate of 3.5 m/s' for

Physics

1 answer:

yaroslaw [1]3 years ago

3 0

Answer: vf = 51 m/s and d= 112 m

Explanation: Solution attached.

You might be interested in

joshua started cycling at 5:15pm. by 8:09 pm, he has covered a distance of 7250m. what was joshua's average speed during that ti

ser-zykov [4K]

Answer:

2,500m/h

Explanation:

Average speed is calculated as total speed traveled divide by total time taken:

$s_{avg}=\frac{d_{total}}{t_{total}}$

Given total distance as 7250m and total time as $2009-1715hrs= 2hrs \ 54min=2.9hrs$ , speed is calculated as :

$s_{avg}=\frac{d_{total}}{t_{total}}\\\\s_{avg}=\frac{7250m}{2.9hrs}\\\\=2500\ m/h$

Hence, Joshua's speed is 2,500m/h

8 0

3 years ago

A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms

Aleonysh [2.5K]

Explanation:

It is given that,

Power of EM waves, P = 1800 W

We need to find the intensity at a distance of 5 m. Also, the rms value of the electric field.

Intensity,

$I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{1800}{4\pi\times (5)^2}\\\\I=5.72\ W/m^2$

The formula that is used to find the rms value of the electric field is as follows :

$I=\epsilon_o cE^2_{rms}$

c is speed of light and $\epsilon_o$ is permittivity of free space

So,

$E_{rms}=\sqrt{\dfrac{I}{\epsilon_o c}}\\\\E_{rms}=\sqrt{\dfrac{5.72}{8.85\times 10^{-12}\times 3\times 10^8}}\\\\E_{rms}=46.41\ V/m$

Hence, this is the required solution.

4 0

3 years ago

Describe the climate and name the climate zone at alaska; portland, oregon; and key west, florida.

Tpy6a [65]

Alaska- Subartic Climate
Portland, Oregon- Marine West Coast Climate
Key West, Florida- Tropical Savannah Climate

3 0

3 years ago

Find the average velocity of the object from point B to C.

ExtremeBDS [4]

The average velocity of the object in moving from point-B to point-C is

(the straight-line distance and direction from point-B to point-C)
divided by
(the time the object takes to make the trip) .

6 0

3 years ago

How much heat does a freezer need to remove from 1kg of water at 40°C to make ice at 0°C? (You will need to use the specific hea

Montano1993 [528]

Answer:

Explanation:

Q = m c Δt

heat withdrawn to lower temperature by 40° C

Q = 1 X 1000 X 40 = 40,000 calories.

Q = mL

heat withdrawn to freeze water at 0°C to ice

= 1 x 80000 = 80,000 calories

total heat to be withdrawn = 120,000 calories. = 120,000 x 4.2 = 504 ,000 Joules.

3 0

3 years ago