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motikmotik
3 years ago
13

Find the average velocity of the object from point B to C.

Physics
1 answer:
ExtremeBDS [4]3 years ago
6 0
The average velocity of the object in moving from point-B to point-C is

                 (the straight-line distance and direction from point-B to point-C)
divided by
                 (the time the object takes to make the trip) .
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A 60 kg swimmer at a water park enters a pool using a 2 m high slide. Find the velocity of the swimmer
koban [17]

Answer:

the velocity of the swimmer at the bottom of the slide is 6.26 m/s

Explanation:

The computation of the velocity of the swimmer at the bottom of the slide is given below:

v = √2gh

= √2 × 9.8 × 2

= 6.26 m/s

Hence, the velocity of the swimmer at the bottom of the slide is 6.26 m/s

5 0
3 years ago
A horizontal force FFaa���⃗ of magnitude 20.0 N is applied to a 3.00 kg psychology book as the book slides a distance d = 0.500
alina1380 [7]

Answer:

(a) W = 8.66 J

(b) Velocity = 2.40 m/s

Explanation:

(a) Work done is given as the product of force and displacement. That is:

W = F * d * cos(A)

Where F = force applied

d = distance moved

A = angle of ramp

Therefore, work done is:

W = 20 * 0.5 * cos30

W = 8.66 J

(b) Work done is equal to change in Kinetic energy. Since the initial kinetic energy is zero:

W = KE(final)

W = ½ * m * v²

Where v = final velocity

=> 8.66 = ½ * 3 * v²

v² = 5.773

v² = 2.40 m/s

7 0
3 years ago
A gas is compressed at constant temperature from a volume of 5.68 L to a volume of 2.35 L by an external pressure of 732 torr. C
Vlada [557]

Answer: The work done in J is 324

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

W=-P\Delta V=-P(V_2-V_1)

W = amount of work done = ?

P = pressure = 732 torr = 0.96 atm    (760torr =1atm)

V_1 = initial volume = 5.68 L

V_2 = final volume = 2.35  L

Putting values in above equation, we get:

W=-0.96atm\times (2.35-5.68)L=3.20L.atm

To convert this into joules, we use the conversion factor:

1L.atm=101.33J

So, 3.20L.atm=3.20\times 101.3=324J

The positive sign indicates the work is done on the system

Hence, the work done for the given process is 324 J

5 0
4 years ago
What forces are used to jump over a wall?
k0ka [10]

Answer:

Potential and kinetic

Explanation:

4 0
3 years ago
You and a friend each carry a 15 kg suitcase up two flights of stairs, walking at a constant speed. Take each suitcase to be the
AlekseyPX

Answer:

Both of you did the same work but you expended more power.

Explanation:              

<em>Work done</em> by an object is calculated by force applied multiplied by the distance.

  W=F*d

From the figure given below let us calculate force applied bith you and yopur friend.

Let us take the stairs in positive x direction,

Work done by you W₁ ,

The force applied Fₓ = F - mgsinθ =maₓ

here aₓ = 0, because both of you move with constant speed

F - mgsinθ = 0

F=  mgsinθ

The work done by you on the suitcase is

W = F L cos0°  ,    where L is he length of the staircase.

W = FL = mgsinθL ,  by substituting value of F

Work done by you is W₁ = mgLsinθ

Similarly work done by your friend is W₂ = mgLsinθ.

Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .

Therefore <em>work done by both of you is same</em> . Both of you did equal work.

The power , is defined as amount of energy converted or transfered per second or rate at which work is done .

P =\frac{W}{t} =\frac{FL}{t}

Power spend by you P₁ = mgLsinθ/t

P₁ = 15*9.8*Lsinθ/30

P₁ = 4.9L sinθ  eqn 1

Power spend by your friend is P₂ = mgLsinθ/t

P₂ =15*9.8*Lsinθ/60

P₂ = 2.45Lsinθ    eqn 2

Dividing eqn 1 and eqn 2

P₁ = 2P₂

You have spend more power than your friend .

Hence Both of you did equal work but you spend more power.

7 0
4 years ago
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