5.610^-26 m is closest to the wavelength of the light.
E=K.E - Work function
hc/λ=1.10-4.65
hc/λ=3.50
λ=hc/3.50
λ=6.626×10 −34J⋅s×3×10^8
λ=5.610^-26 m
Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.
The wavelength of electromagnetic radiation affects its behavior. The speed of light is equal to wavelength times frequency. Frequency multiplied by the Planck constant equals energy. 1/wavelength is the wave number in cm. Along with the wavelengths of different parts of the electromagnetic spectrum, a rough estimation of the wavelength size is displayed.
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Answer:
Option C
Explanation:
We have to check range of all options first
For A:
Largest Value: 5
Smallest Value: 1
So range = Largest value - smallest value
5-1 = 4
For B:
Largest Value: 6
Smallest Value: 4
Range = 6-4 = 2
For C:
Largest Value: 9
Smallest Value: 1
Range = 9-1 = 8
For D:
Largest Value = 9
Smallest Value = 3
Range = 9-3=6
So, the data set in option C has the largest range
Explanation:
potential energy =360800J
mass(m)=?
height (h)=25m
g=9.8m/s²
we have
potential energy =360800J
mgh=360800J
m×9.8×25=360800
m=360800/(9.8×25)=1472.653061kg
Answer:
Explanation:
Initial kinetic energy of M = 1/2 M vi²
let final velocity be vf
v² = u² + 2a s
vf² = vi² + 2 (F / M) x D
Kinetic energy
= 1/2 Mvf²
= 1/2 M ( vi² + 2 (F / M) x D
1/2 M vi² + FD
Ratio with initial value
1/2 M vi² + FD) / 1/2 M vi²
RK = 1 + FD / 2 M vi²