Classify the following triangle. Check all that apply

8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components

Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability, and has variance given by:

$V(X) = np(1 - p)$

In this problem:

95% pass final inspection, hence $p = 0.95$

120 components are inspected in one day, hence $n = 120$ .

The variance is given by:

$V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7$

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0

2 years ago

There are 442 boy students in class

poizon [28]

Answer:

520

Step-by-step explanation:

This problem is

boys + girls = total

Boys = 442

Girls = 15% of the total

Therefore, substituting in, gives us:

442 + .15t = t, where t is total

Then 442 = .85t and

t = 520

5 0

3 years ago

a bastetball is passed through the air. The height h of the ball in feet after the distance d in feet the ball travels horizonta

Ksenya-84 [330]

You want the (positive) distance when the height is 0, 0= -d^2 + 10d +5. You would factor that out(You'd get radicals), and the final answer would be 5±30−−√ You'd take the only positive one of the two, 5 + srt(30) I hope I did that right :/

3 0

4 years ago

Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r

igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0

3 years ago

Lee spent 1/3 of his money on a jacket then he spent 1/4 of he remainder on a skirt how much did his spend on the skirt and how

serg [7]

How is it possible to know how much he started with? Or is it not asking for an exact amount?

6 0

3 years ago