Answer: 18
Step-by-step explanation:
The formula to find the minimum sample size is given by :_

, where
= population standard deviation.
z*= critical z-value.
E= Margin of error.
Given : 
E= ± 8
We know that critical value corresponding to 99% confidence level = z*=2.576 [Using z-table]
Then, the required sample size would be :


[Round to next integer.]
Hence, the required minimum sample size = 18
1/2 x 6 = 3
3 x 8 = 24
24/6 = 4
4 - 1 = 3
3 is your answer
hope this helps
Answer:
Step-by-step explanation:
a) The formula for determining the standard error of the distribution of differences in sample proportions is expressed as
Standard error = √{(p1 - p2)/[(p1(1 - p1)/n1) + p2(1 - p2)/n2}
where
p1 = sample proportion of population 1
p2 = sample proportion of population 2
n1 = number of samples in population 1,
n2 = number of samples in population 2,
From the information given
p1 = 0.77
1 - p1 = 1 - 0.77 = 0.23
n1 = 58
p2 = 0.67
1 - p2 = 1 - 0.67 = 0.33
n2 = 70
Standard error = √{(0.77 - 0.67)/[(0.77)(0.23)/58) + (0.67)(0.33)/70}
= √0.1/(0.0031 + 0.0032)
= √1/0.0063
= 12.6
the standard error of the distribution of differences in sample proportions is 12.6
b) the sample sizes are large enough for the Central Limit Theorem to apply because it is greater than 30
Answer:
360 votes
Step-by-step explanation:
Move the decimal to the left 2 times and you'll get .144. Multiply that by 2500, and you have your answer.