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fredd [130]
2 years ago
7

Please help. What is this called.​

Mathematics
1 answer:
borishaifa [10]2 years ago
4 0

<u>Error</u><u> </u><u>Function</u><u> </u><u>of</u><u> </u><u>z</u><u> </u><u>{</u><u>erf</u><u>(</u><u>z</u><u>)</u><u>}</u>

Step-by-step explanation:

It is a much used function in statistics, fluid mechanics and thermodynamics.

It just tells the probability.

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Suppose that the functions and s are defined for all real numbers x as follows.
abruzzese [7]

(r*s) = (x+1)(3x+4) = 3x² + 3x + 4x + 4 = 3x² + 7x + 4

(r-s)(x) = x+1 - (3x+4) = x + 1 - 3x - 4 = -2x - 3

(r+s)(x) = x + 1 + 3x + 4 = 4x + 5

(r + s)(2) = 4(2) + 5 = 8 + 5 = 13

<h3>What is algebraic expression?</h3>

A number, a variable, or a mix of numbers, variables, and operation symbols make up an expression. Two expressions joined by an equal sign form an equation. Word illustration: The product of 8 and 3. Word illustration: The product of 8 and 3 is 11

to learn more about algebraic expression refer to:

brainly.com/question/4344214

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Let f(x)=3x2+2x−3. What is f(3)?
Annette [7]

Answer:

f(3) = 30

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x² + 2x - 3

f(3) is x = 3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(3) = 3(3)² + 2(3) - 3
  2. Exponents:                          f(3) = 3(9) + 2(3) - 3
  3. Multiply:                               f(3) = 27 + 6 - 3
  4. Add:                                     f(3) = 33 - 3
  5. Subtract:                              f(3) = 30
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6. (x + 2)(3x - 1) - (x + 4)(x - 7)<br> i’m confused
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Answer:

\large\boxed{(x+2)(3x-1)-(x+4)(x-7)=2x^2+8x+26}

Step-by-step explanation:

(x+2)(3x-1)-(x+4)(x-7)\\\\\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x+2)(3x-1)=(x)(3x)+(x)(-1)+(2)(3x)+(2)(-1)\\\\=3x^2-x+6x-2=3x^2+(-x+6x)-2=3x^2+5x-2\\\\(x+4)(x-7)=(x)(x)+(x)(-7)+(4)(x)+(4)(-7)\\\\=x^2-7x+4x-28=x^2+(-7x+4x)-28=x^2-3x-28\\\\(x+2)(3x-1)-(x+4)(x-7)=(3x^2+5x-2)-(x^2-3x-28)\\\\=3x^2+5x-2-x^2-(-3x)-(-28)=3x^2+5x-2-x^2+3x+28\\\\=(3x^2-x^2)+(5x+3x)+(-2+28)\\\\=2x^2+8x+26

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