Please help me with 168÷45

const2013 [10]

One way to write 18/6 is to compute 18/6 to be the whole number of a quotient that is equal to. Another way to write 18/6 is to write it as an improper fraction that's reduced. One more way to write 18/6 is as a decimal. Note how all of these ways of writing the same expression are all equal to writing one same value, and it's the WAY in which you modify what you're writing.

3 0

3 years ago

What is the answer for this problem 3-3×6+2=?

liberstina [14]

Answer:

-13

Im correct!

6 0

3 years ago

Read 2 more answers

40 POINTS! DONT MISS OUT!

e-lub [12.9K]

Answer:

3y - 2x

Step-by-step explanation:

3 0

3 years ago

What is the difference between (Picture 1) and (picture 2)? A. 0 B. 2 C. 5 D. 6

Vesnalui [34]

Answer:

The difference between the picture is 0 , option A .

Step-by-step explanation:

Given two figures as :

In figure A

The expression is 1 + 3 n , where n lies from 0 to 4

So , let f (n) = 1 + 3 n

Or,f ( n ) = 1 + 3 ×0 = 1 + 0 = 1

f ( 1 ) = 1 + 3 ×1 = 1+ 3 = 4

f ( 2 ) = 1 + 3 ×2 = 1+ 6 = 7

f ( 3 ) = 1 + 3 ×3 = 1+ 9 = 10

f ( 4 ) = 1 + 3 ×4 = 1+ 12 = 13

so, summation of ( 1 + 3 n ) from n = 0 to 4 = 1 + 4 + 7 + 10 + 13 = 35

In figure B

The expression is 3 i - 5 , where i lies from 2 to 6

So , let g (i) = 3 i - 5

Or,g ( 2 ) = 3 ×2 - 5 = 6 - 5 = 1

g ( 3 ) = 3 ×3 - 5 = 9 - 5 = 4

g ( 4 ) = 3 ×4 - 5 = 12 - 5 = 7

f ( 5 ) = 3 ×5 - 5 = 15 - 5 = 10

f ( 6 ) = 3 ×6 - 5 = 18 - 5 = 13

so, summation of ( 3 i - 5 ) from i = 2 to 6 = 1 + 4 + 7 + 10 + 13 = 35

So, The difference between the summation of functions f(n) - g(i) is

f(n) - g(i) = 35 - 35

I.e f(n) - g(i) = 0

Hence The difference between the picture is 0 , option A . Answer

4 0

3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

Please help me with 168÷45​

Please help me with 168÷45