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2 years ago

9

HURRY ITS URGENT!!!!

1 answer:

MArishka [77]2 years ago

5 0

It has to be either A or B

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What is the easiest way to add negative fractions?

otez555 [7]

Ayou do it the exact same as whole number fractions but you might have to be more mindfull of the decimals

Step-by-step explanation:

4 0

3 years ago

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A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

3 years ago

How many times does 7 go into 19

Svetllana [295]

7 goes into 19 2 complete times. 7*2=14, but 7*3=21

the true answer is a decimal, one around 2.71

6 0

3 years ago

Is 16 divided by 3 a repeating decimal

Nady [450]

Answer:

Yes

Step-by-step explanation:

16 ÷ 3 = 5.333333...

3 0

3 years ago

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Write the equation of the line passing through the points (2,-5) and (7,-3).

Grace [21]

Answer:

5y·2x=21

<em> $\frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1}$ </em>

Step-by-step explanation:

using the formula above,you will find the equation 5y–2x=21

7 0

3 years ago