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emmasim [6.3K]
2 years ago
13

What is the surface area of the triangular prism shown?

Mathematics
1 answer:
Lunna [17]2 years ago
4 0

Answer:

The first step that we are going to do is to solve the area of the top rectangle.  We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 15\ cm

Area = 375\ cm^2

The second side that we are going to solve for is the bottom rectangle.  We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 12\ cm

Area = 300\ cm^2

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 9\ cm

Area = 225\ cm^2

The final area that we have to determine are the side triangles.  After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles.  We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

Area = \frac{1}{2}* b*h

Area = \frac{1}{2}* 12\ cm*9\ cm

Area = 54\ cm^2

Multiply it by two to get the area for both of the triangles.

Area = 54\ cm^2 * 2

Area = 108\ cm^2

Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.

Area_{total}=375\ cm^2 + 300\ cm^2 + 225\ cm^2 + 108\ cm^2

Area_{total}=1008\ cm^2

Therefore, our final answer is option B, 1008 cm^2

Hope this helps!

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Given : Angle  < CEB is bisected by EF.

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