75+ 15x ≥ 140
⇒ 15x ≥ 140-75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3
Final answer: x ≥ 4 1/3~
In the given question, there are numerous information's already provided. It is important to note then down first. With the help of those given information's the required answer can be easily reached.
Percentage of students that weighed 140 pounds = 75 percent
Then
Percentage of students that weighed more than 140 pounds = (100 - 75) percent
= 25 percent
Total number of students that were weighed = 40 students
Total number of students that weighed more than 140 pounds = (25/100) * 40
= (40/4) students
= 10 students
So the number of students that weighed more than 140 pounds is 10. So the correct option in regards to the given question is option "1".
Answer:
8
Step-by-step explanation:
3(8-m)=5m-40
you first distribute 3 through the parenthesis
24-3m=5m-40
Move the variable to the left and change sign
24-3m-5m=-40
now move the constant to the right
-3m-5m=-40-24
collect like terms
-8m=-40-24
-8m=-64
Divide both sides by -8 and negative divide negative number becomes positive
so m = 8
Answer: -16
Step-by-step explanation:
Let the number be y
Four times a number minus twenty-one can be written as:
(4 × y) - 21 = 4y - 21
Six times the number plus eleven can be written as:
(6 × y) + 11 = 6y + 11
Combining both equations will give:
4y - 21 = 6y + 11
4y - 6y = 11 + 21
-2y = 32
y = 32/-2
y = -16
The number is -16
Answer:
P(5, 1)
Step-by-step explanation:
Segment AB is to be partitioned in a ratio of 5:3. That means the ratio of the lengths of AP to PB is 5:3. We need to find the ratio of the lengths of AP to AB.
AP/PB = 5/3
By algebra:
PB/AP = 3/5
By a rule of proportions:
(PB + AP)/AP = (3 + 5)/5
PB + AP = AP + PB = AB
AB/AP = 8/5
AP/AB = 5/8
The first part of the segment is 5/8 of the length of the segment, and the second part of the segment has length of 3/8 of the length of segment AB.
Point P is located 5/8 of the distance from point A to point B. The x-coordinate of point P is 5/8 of the difference in x-coordinates added to the x-coordinate of point A. The y-coordinate of point P is 5/8 of the difference in y-coordinates added to the y-coordinate of point A.
x-coordinate:
difference in coordinates: |14 - (-10)| = |14 + 10| = 24
5/8 of 24 = 5/8 * 24 = 15
Add 15 to the x-coordinate of point A: -10 + 15 = 5
x-coordinate of point P: 5
y-coordinate:
difference in coordinates: |4 - (-4)| = |4 + 4| = 8
5/8 of 8 = 5/8 * 8 = 5
Add 5 to the y-coordinate of point A: -4 + 5 = 1
y-coordinate of point P: 1
Answer: P(5, 1)
