All categories

3 years ago

6(4.5y – 12) = 9 can someone help me anwser this please

Mathematics

1 answer:

quester [9]3 years ago

3 0

Answer: y=3

Step-by-step explanation: 6(4.5y−12)=9

Step 1: Simplify both sides of the equation.

6(4.5y−12)=9

(6)(4.5y)+(6)(−12)=9(Distribute)

27y+−72=9

27y−72=9

Step 2: Add 72 to both sides.

27y−72+72=9+72

27y=81

Step 3: Divide both sides by 27.

27y/27 =81/27

You might be interested in

Write each phrase as a variable expression:<br><br> 9 subtracted from x

Schach [20]

Answer:

9-x

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Stacy started a banking account with $150 and is spending $7 per day on lunch. This situation models which type of function?

Lubov Fominskaja [6]

Answer:

Linear

Step-by-step explanation:

She is spending the same amount per day, so it is linear

8 0

3 years ago

Please and thank you to whoever helps

Zepler [3.9K]

Answer:

1131.0 m³

Step-by-step explanation:

Using the formula for the volume of a cylinder, fill in the appropriate values and do the arithmetic.

V = πr²h

Since this formula needs the radius of the cylinder and you are given the diameter, you must divide the diameter by 2 to get the radius:

r = d/2 = (12 m)/2 = 6 m

Then the volume is ...

V = π(6 m)²(10 m) = 360π m³ ≈ 1131.0 m³ . . . . . rounded to tenths

8 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago

-)) Aiden ordered a set of beads. He received 150 beads in all. 24 of the beads were brown. What

vesna_86 [32]

Answer:

16 %

Step-by-step explanation:

(24/150) . 100 = 16

5 0

2 years ago