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2 years ago

I need help ASAP!!!!

Mathematics

1 answer:

dexar [7]2 years ago

3 0

It’s the 2nd answer to the right

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Hi pls helpppppp. thank uuu :)

tamaranim1 [39]

Answer:

-7/4

Step-by-step explanation:

Slope is (y₂ - y₁) / (x₂ - x₁)

Using this, plug in the values they give.

(6 - (-1)) / (-4 - 0)

Simplify.

7 / (-4)

-7 / 4

The slope is - 7/4, or -1 3/4 ( negative 1 and three fourths)

I hope this helps! Feel free to ask any questions!

5 0

2 years ago

5 pens for 14 dollars rounded to the nearest hundred

tatiyna

Answer:

Step-by-step explanation:

Your dumb

7 0

2 years ago

What is an equivalent expression for 3a + 5 ?

Georgia [21]

Answer:

Equivalent expression:

6a + 10

9a + 15

6 0

3 years ago

Which describes Myra's distance as time increases?

DaniilM [7]

Answer:

(A)increasing

Step-by-step explanation:

Given the time and total distance ran by Myra in the table below.

$\left|\begin{array}{c|c}Time(minutes)&Distance(miles)\\--&--\\0&0.0\\2&0.4\\4&0.8\\6&1.2\\8&1.6\end{array}\right|$

We observe that as time increases, Myra's distance also increases. It is the speed(0.2 miles per minute) which is constant.

Therefore Option A is the correct option.

3 0

2 years ago

Read 2 more answers

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

2 years ago