The equivalent value of the sum for any value of "x" is 12x - 6
<h3>How to find the sum of functions?</h3>
Given the sum of the expression as:
3
∑ k(2x-1)
k=0
We need to take the sum of the function at the point where k = 0 to 3
3
∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)
k=0
3
∑ k(2x-1) = 2x-1+4x-2+6x-3
k=0
3
∑ k(2x-1) = 12x - 6
k=0
Hence the equivalent value of the sum for any value of "x" is 12x - 6
Learn more on sum functions here: brainly.com/question/24295771
This formula means that a(n) for n, when n is the term number, will give you the term. Meaning, we just have to plug in 55 for n.
a(55) = -1 + 3(55 - 1)
a(55) = -1 + 3 * 54
a(55) = -1 + 162
a(55) = 161
If you recall y=mx+b, the slope-intercept form of a linear equation, the slope, m, is the rate of change of the equation, and the y-intercept is b.
When switching to function notation, we simply swap y for f(x), and if we start at x=0 and graph in the positive x direction, we've started at whatever initial value exists (the y-intercept value).
Simply: F(x) = 2/3 x + 4
5.57 because 5 is the tenths 6 is hundredths 7 is thousandths
= 144