Answer:
a. 0.4
b. 0.6
c. 0.6493
Step-by-step explanation:
p(checking work email) = p(A) = 0.40
p(staying connected with cell phone) = p(B) = 0.30
p(having laptop) = p(c) = 0.35
p(checking work mail and staying connected with cell phone) = p(AnB) = 0.16
p(neither A,B or C) = p(AuBuC)
= 1-42.8%
= 0.572
p(A|C) = 88% = 0.88
p(C|B) = 70% = 0.7
a. What is the probability that a randomly selected traveler who checks work email also uses a cell phone to stay connected?
p(B|A) = p(AnB)/p(A)
= 0.16/0.4
= 0.4
b. What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected?
p(B|C) = P(C|B)p(B)/p(C)
= 0.7x0.3/0.35
= 0.6
c. If the randomly selected traveler checked work email and brought a laptop, what is the probability that he/she uses a cell phone to stay connected?
p(A|BnC)
= P(BnAnC)/p(AnC)
= p(AnC) = p(A|C).p(C)
= 0.88x0.35
= 0.308
p(AnBnC) = p(AuBuC)-p(a)-p(b)+ p(AnB)+p(AnC)+p(BnC)
p(BnC) = 0.7x0.3
= 0.21
p(AnBnC) = 0.572-0.4-0.3-0.35+0.16+0.308+0.21
= 0.2
p(A|BnC) = 0.2/0.308
= 0.6493
-5c^2-3c+4 This polynomial is in standard form, now, and the leading coefficient is 5, because it is the coefficient of the first term. Degree is 2, due to -5c^2.
Answer:
SAS postulate
Step-by-step explanation:
Answer: The selling price of the coffee maker is $92.04
If the original cost is $76.70 but the company wants to make profit from the product, meaning they want to sell it higher than what they purchased it for in order to gain money, then you add the markup cost to the original cost (20%).
$76.70 + 20% of $76.70
=$76.70 + $15.34
=$92.04 selling price of coffee maker.
Answer:
-6x-22
Step-by-step explanation:
-6 -2 (3x + 8)
Distribute the 2.
-6 -6x -16
Rewrite the expression.
-6x -6 - 16
Subtract -6 from 16.
The answer is -6x-22
