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1 year ago

The top of the table can be modeled with a cylinder, and the legs can be modeled with rectangular prisms.

Mathematics

2 answers:

Solnce55 [7]1 year ago

8 0

The answer is B 3,703 in2

Alik [6]1 year ago

6 0

The answer would be B 3,703 for the top of the table that needs to be covered to the nearest square inch.

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I need help plz you leave you house at 1 p.m to go to a wedding. The ceremony starts at 5 p.m. and is 350 miles away. You drive

3241004551 [841]

You leave at 1 P.M., the wedding ceremony starts at 5 P.M.

This gives you a 4 hour gap, the Wedding is 350 miles away, and you're traveling at 65 miles an hour.

Simply you can use two methods, (65 * 4) to verify if you'd make it or not or (350/65) to ensure how many hours it would take in total.

65 * 4 = 260 | Since this is not 350, we can verify that you'd be late.
350/65 = 5.4 (estimated) | Meaning it'd take about 5.4 hours.

To know how long that is we'd have to convert over.

5.4 = 5 2/5ths, 60 minutes are in an hour. Divide 60 by 5 to get 12, meaning:
1/5ths = 12/60ths, with that said multiply that by 2 to get your answer.
2/5ths = 24/60ths or 24 minutes.

This means you'd take 5 hours and 24 minutes to get there.

Originally we stated that the process would take 4 hours. Subtract:

(5 hours and 24 minutes) - (4 hours) = (1 hour and 24 minutes)

Concluding that you'd be late by an hour and 24 minutes.

I hope this helps, have a great rest of your day! ^ ^
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4 0

3 years ago

Can Someone Please Help Me With This Question. I'll post a picture of the question

Vedmedyk [2.9K]

Answer:

$y-7=3(x-9)$

Step-by-step explanation:

The form of equation of line given in the problem is the point-slope form of a line. That is given by:

$y-y_1=m(x-x_1)$

We need $y_1$ and m (denoted by boxes)

$y_1$ is the y coordinate of the first set of points.

The first coordinate pair is (9,7), so $y_1$ would be 7

$y_1=7$

Now, the slope (m).

It has formula

$m=\frac{y_2-y_1}{x_2-x_1}$

So, x_1 = 9

y_1 = 7

x_2 = 4

y_2 = -8

Substituting, we get the slope to be:

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-8-7}{4-9}\\m=\frac{-15}{-5}\\m=3$

Hence, the equation of the line in point-slope is:

$y-7=3(x-9)$

5 0

2 years ago

Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit

ikadub [295]

The square (call it $S$ ) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is $\vec n=\vec\imath-\vec k$ , which is enough information to figure out the equation of the plane containing $S$ :

$(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x$

We can parameterize this surface by

$\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k$

for $0\le x\le\frac3{\sqrt2}$ and $0\le y\le3$ . Then the flux of $\vec F$ , assumed to be

$\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k$ ,

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}$

3 0

3 years ago

What are the missing values in the following geometric sequence? __, 6, 3, __, __.

9966 [12]

The missing numbers are 12, 1.5, and 0.75 because it gets divided by 2 (or multiplied by 0.5) each time.

hope this helps.

7 0

3 years ago

Wake up cereal comes in 2 types, crispy and crunchy. If researcher has 10 boxes of each, how many ways can this be done?

Yuliya22 [10]

Answer:

11 ways

Step-by-step explanation:

10 crunchy

9 crunchy 1 crispy

8 crunchy 2 crispy

7 crunchy 3 crispy

6 crunchy 4 crispy

5 crunchy 5 crispy

4 crunchy 6 crispy

3 crunchy 7 crispy

2 crunchy 8 crispy

1 crunchy 9 crispy

10 crispy

8 0

3 years ago