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Answer:
P-value is less than 0.999995 .
Step-by-step explanation:
We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.
Null Hypothesis, :
{means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}
Alternate Hypothesis, :
{means students who took the driver's education course were more likely to pass the written driver's exam the first time}
The test statistics used here will be two sample Binomial statistics i.e.;
~ N(0,1)
Here, = No. of students passed the exam ÷ No.of Students that had taken the course
=
Similarly,
=
= 1,850
= 1,500
Test Statistics = = -27.38
P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)
Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .
2/5+-1/3 please excuse my sloppy writing
