Answer:
x=9
Step-by-step explanation:
I hope this helps you
16x+4=110+3x+11
13x=117
x=9
x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
Answer:
maximum value y = 30
Step-by-step explanation:
Given
- x² + 10x + 5
To complete the square the coefficient of the x² term must be 1
factor out - 1
= - (x² - 10x) + 5
To complete the square
add/subtract ( half the coefficient of the x- term )² to x² - 10x
= - (x² + 2(- 5)x + 25 - 25) + 5
= - (x - 5)² + 25 + 5
= - (x - 5)² + 30 ← in vertex form
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Hence vertex = (5, 30)
The max/ min occurs at the vertex
Since a < 0 then vertex is a maximum
Hence maximum value is y = 30
Given:
Point is T(-3,8).
To find:
The coordinates of T' after 
.
Solution:
We know that, means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then
If a figure reflected across y-axis, then
Therefore, the required point is T'(3,-8).
