Based on the given condition, since the rectangle is inscribed in a circle given the length to be 3x, the width can be approximated by taking the right triangle formed by the radius and the w/2, sin 45 = w/2/r, which is equal to w = 2r sin45, therefore the Area of the inscribed rectangle = LxW = (3x)(2rsin45)
Answer:
The general admission ticket number is 160 and the upper box ticket number is 136
Step-by-step explanation:
In this case we can solve it using a 2x2 system of equations, like this:
let x be general admission tickets number
let y be upper box tickets number
So:
6.5 * x + 10 * y = 2400
x + y = 296 => x = 296 - y
Replacing, we are left with that:
6.5 * (296 - y) + 10 * y = 2400
1924 - 6.5 * y + 10 * y = 2400
10 * y - 6.5 * y = 2400 - 1924
3.5 * y = 476
y = 476 / 3.5
y = 136
Now to calculate x:
x = 296 - 136
x = 160
The general admission ticket number is 160 and the upper box ticket number is 136
-22-x=5+6x+9
-6x-x=22+5+9
-7x=36
x=5.142
Plug in numbers in for x.
If you plug in 0 then you get 1. 1/0 is undefined
If you plug in 1 then you get 6. 6/1 is 6
If you plug in 2 then you get 11. 11/2 is 5.5
If you plug in 3 then you get 16. 16/3 is 5.3 repeating
If you plug in 4 then you get 21. 21/4 is 5.25
If you plug in 5 then you get 26. 26/5 is 5.2
It would only be proportional if you got the same answer after dividing each time.
Answer:
5 and 4
Step-by-step explanation:
So if, x equals 2 then all you do is turn the x into a 2.
So you rewrite the equation into,
2 + 3 and 2 x 2,
Which would be 5 and 4
Hope this helps!