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Sladkaya [172]
2 years ago
14

Triangle DEF is translated 3 units up to form triangle D'E'F'and 5 units to the left to form triangle D''E'' ''F'. The coordinat

es of vertex F in triangle DEF are
(2, -4)
What are the coordinates of F''
Mathematics
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

(7,-2)

Step-by-step explanation:

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Which statement is true regarding the graphed functions?
RoseWind [281]

Answer:c. F(2)=g(-2)

Step-by-step explanation:

4 0
3 years ago
When can you use mixed numbers in real life
ch4aika [34]

Answer:

You can use mixed numbers in the real world when you are baking there are measuring cups like for example... 1 1/2 of sugar. You can also use mixed numbers in the real world when you are sharing thins like cake or a pizza. You can use mixed numbers for some things.

I did that picture for homework hope that helped .

3 0
3 years ago
Carla wants to start a college fund for her daughter Lila. She puts $63,000 into an account that grows at a rate of 2.55% per ye
Oksanka [162]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 63000

r = 2.55% = 2.55/100 = 0.0255

n = 12 because it was compounded 12 times in a year.

Therefore, function, C(t), that represents the amount of money in the account t years after the account is opened is

C(t) = 63000(1 + 0.0255/12)^12t

C(t) = 63000(1.002125)^12t

For C(t) = 100000,

100000 = 63000(1.002125)^12t

100000/63000 = (1.002125)^12t

1.587 = 1.002125)^12t

Taking log of both sides

Log 1.587 = log 1.002125)^12t

Log 1.587 = 12tlog 1.002125)^

0.2005 = 12t × 0.00092

0.2005 = t × 0.01104

t = 0.2005/0.01104

t = 18.16 years

5 0
3 years ago
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
2 years ago
Going 65 mph and going 145 miles. How many hours to reach destination?
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Where is the starting and stopping point?
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