Answer:
109
Step-by-step explanation:
You can brute-force this:
Candidate numbers that are divisable by 13 if you take away 5: 18
, 31
, 44
, 57
, 70
, 83
, 96
, <u>109
</u>, 122
, 135
, 148
Candidate numbers that are divisable by 14 if you take away 11: 25
, 39
, 53
, 67
, 81
, 95
, <u>109
</u>, 123
, 137
Only 109 is in both lists.
Answer:
this is my answer for this question
21.5
Hello from MrBillDoesMath!
Answer:
The first choice ( -12, 20)
Discussion:
Using matrix multiplication we find the equations:
1x + 1y = 8 (A)
2x + 3y = 36 (B)
Next, compute
2(A) - B =>
(2x + 2y) - (2x + 3y) = 2*8 - 36 =>
(2x - 2x) + ( 2y-3y) = 16 - 36 =>
-y = -20 =>
y = 20
Substituting this y value in (A) gives
x + 20 = 8 =>
x = 8 - 20 =>
x = -12
The answer is the first choice ( -12, 20)
Thank you,
MrB
The answer is 20 because all 4 sides would equal 5
