Answer:
Second class have higher marks and greater spread.
Step-by-step explanation:
First box plot represents class first. From the first box plot, we get
Second box plot represents class second. From the second box plot, we get
First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.
Second class has greater range and greater inter quartile range. It means data of second class has greater spread.
Therefore, second class have higher marks and greater spread.
Answer:
2,674.14 g
Step-by-step explanation:
Recall that the formula for radioactive decay is
N = N₀ e^(-λt)
where,
N is the amount left at time t
N₀ is the initial amount when t=0, (given as 42,784 g)
λ = coefficient of radioactive decay
= 0.693 ÷ Half Life
= 0.693 ÷ 18
= 0.0385
t = time elapsed (given as 72 years)
e = exponential constant ( approx 2.7183)
If we substitute these into our equation:
N = N₀ e^(-λt)
= (42,787) (2.7183)^[(-0.0385)(72)]
= (42,787) (2.7183)^(-2.7726)
= (42,787) (0.0625)
= 2,674.14 g
Step-by-step explanation:
1.
2.
3.
4.
5.
<span>1. Make y the subject
a) 4y=12x+18
y = 3x + 4.5
b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3
2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)
slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1
equation
y = 2.5x + 1
b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)
</span>y= 1/2X + 7
slope = 1/2
slope of line perpendicular = -2
passing through point (3,9)
y = mx + b
9 = -2 (3) + b
b = 15
equation
y = -2x + 15
His stomach is gonna hurt really bad
