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ivanzaharov [21]
3 years ago
8

Pls someone answer me in correct way

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0
0/2=0
.........................
pogonyaev3 years ago
3 0
2nd line:
output y=0, ordered pair (0, 0)
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Rename 2/5 as a percent_______________________
loris [4]

It can be helpful to remember that "%" is just a shorthand way to write "/100" (divided by 100, or per 100, or per cent). ("Cent" is often used to refer to 100 or 1/100. A "cent" is 1/100 of a dollar, or 1/100 of an acre, for example. A <em>cent</em>ury is 100 years.)

Make the denominator of your fraction be 100. Multiply numerator and denominator by 20/20.

(2/5)×(20/20) = 40/100 = 40%

You can also get there via decimals.

... 2/5 = 0.4 = 0.40 (40 hundredths) = 40/100 (40 hundredths) = 40%

Or, you can multiply by 100%.

... (2/5)×(100%) = (200/5)% = 40%

7 0
3 years ago
Find the product of monomials<br> 3a^4b^-2 and 2a^7b^-1
Inga [223]
(3a^4 * b^-2) * (2a^7 * b^-1)
= 6*a^(4+7)*b^(-2-1)
= 6*a^11*b^-3
5 0
3 years ago
Describe the image when a scalene triangle is rotated 180 degrees counterclockwise
Luba_88 [7]

Answer:

It is a same size scalene triangle as the original triangle.

Step-by-step explanation:

:)

6 0
3 years ago
Read 2 more answers
Rewrite the equation 4x + 4y = 20 in slope interception form
BARSIC [14]
Equation you asked: 4x +4y = 20, Rewritten equation: -1x + 5 

hope this helps.
4 0
3 years ago
With a capacity of 6,300 people, Royal Caribbean’s Oasis of the Seas is the world’s largest cruise ship. The average beer consum
Mariulka [41]

Step-by-step explanation:

Mean = 81740

Standard deviation = 4590

Sample size = 15

Alpha level = 1-0.95 = 0.05

Df = 15-1 = 14

Critical value:

alpha/2 = 0.05/2 = 0.05

t0.025

t critical value = 2.145

Margin of error ME

2.145 x 4590/√15

2.145 x 4590/3.873

ME = 2542.09

Confidence interval

Lower CI = mean - ME

= 81740-2542.09

= 79197.91

Upper CI = mean + ME

= 81740+2542.09

= 84282.09

[ 79197.91, 84282.09]

B.

Using excel, exact answer for CI

Lower limit = 79198.142724212173

Upper limit = 84281.8572757827

C.

The assumptions to be made from the population are that

1. Samples are random

2. These samples are gotten from an approximately normal distribution

6 0
3 years ago
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