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ivanzaharov [21]
3 years ago
8

Pls someone answer me in correct way

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0
0/2=0
.........................
pogonyaev3 years ago
3 0
2nd line:
output y=0, ordered pair (0, 0)
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Show all work <br> Find exact value of x
Illusion [34]

Answer:

129 is x

Step-by-step explanation:

Your equation would be like this x= 45 + 6=180 (180 because the sum of the angle measures in a triangle is 180 always)

so once you add 45+6 =51 the equation is now x=51=180 so you subtract 51 from both sides so it equals as this x=51=180

                                                                                         x =-51= -51

                                                                                         x=         129

5 0
3 years ago
Evaluate 1/3m-1-1/2n when m=21 and n=12
stellarik [79]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
13. Which system of inequalities has no solution?
Anit [1.1K]

Answer:

Option A

Step-by-step explanation:

We have y < 2x - 4 and y > 2x + 1.

=> 2x - 4 > 2x + 1

=> -4 > 1

Since this inequality is false for all real values of x, there is no solution for the system of inequalities.

8 0
3 years ago
Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
3 years ago
To win at LOTTO in one​ state, one must correctly select 4 numbers from a collection of 50 numbers​ (1 through 50​). The order i
Oksana_A [137]

Answer:

230,300 different selections.

Step-by-step explanation:

If the order does not matter, the number of possible different selections is determined as the combination of choosing four numbers out of 50:

n=\frac{50!}{(50-4)!4!}\\\\n=\frac{50*49*48*47}{4*3*2*1} \\\\n=230,300\ combinations

There are 230,300 possible different selections.

4 0
2 years ago
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