The approximate mass of the spherical weight is 51 pounds
To answer the question, we need to know what the mass of the sphere is
<h3>Mass of the sphere</h3>
The mass of the sphere m = ρV where
- ρ = density of steel = 0.284 lb/in³ and
- V = volume of sphere = 4πr³/3 where
- r = radius of sphere = 3.5 in
So, m = ρV
= ρ4πr³/3
Substituting the values of the variables into the equation, we have
m = ρ4πr³/3
= 0.284 lb/in³ × 4π(3.5 in)³/3
= 0.284 lb/in³ × 4π × 42.875 in³/3
= 48.706π lb/3
= 153.014 lb/3
= 51 lb
The approximate mass of the spherical weight is 51 pounds
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Here,
Perimeter (P)=86 feet
Length (l)=25 feet
Let, width(b)= x feet
Then,
Perimeter= 2(l+b)
86=2(25+x)
43=25+x
x=18
Hence, required width is 18 feet...
Answer:
30 oz of grey
25 oz of brown
Answer:
Let's simplify step-by-step.
(3)(3)−(19)(2)+kx−30
=9+−38+kx+−30
Combine Like Terms:
=9+−38+kx+−30
=(kx)+(9+−38+−30)
=kx+−59
Answer:
=kx−59
