Answer:
See below
Explanation:
Hello there!
Electronegativity is the atom's tendency to attract electrons in a chemical bond
There are two trends to electronegativity:
- Electronegativity increases from bottom to top in a group (Li has a greater electronegativity than Fr, for example)
- Electronegativity increases from left to right across a period (the further right the group, the greater the electronegativity)
Looking at a period table, Sb, Sn, Te, and I are all in the same period, so we'll need to decide which element has the highest electronegativity based on the group.
- Sn belongs to group 4A (group 14)
- Sb belongs to group 5A (group 15)
- Te belongs to group 6A (group 16)
- I belongs to group 7A (group 17)
As I belongs to group 7A, the group that is the farthest right based off of the options given, I has the highest electronegativity
Hope this helps!
To get the ratio of the concentration of sodium acetate to the concentration of acetic acid we are going to use H-H equation:
when:
PH = Pka + ㏒[salt/acid]
when the Ka of acetic acid = 1.75 x 10^-5
so, we can get Pka from this formula:
Pka = -㏒Ka
= -㏒1.75 x 10^-5
= 4.76
and when we have PH = 5.75, so by substitution:
∴ 5.75 = 4.76 + ㏒[acetate/ acetic acid]
∴ [acetate/acetic acid] = 9.77
∴ the ratio of a concentration of acetate to acetic acid 9.77
