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3 years ago

Which equation is derived from the combined gas law

Chemistry

2 answers:

marusya05 [52]3 years ago

5 0

The correct answer is V1/T1=V2/T2. Just took the test

Diano4ka-milaya [45]3 years ago

4 0

P - pressure
V - Volume
T - Temperature

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When 100.g Mg3N2 reacts with 75.0 g H2O, what is the maximum theoretical yield of NH3?

Temka [501]

Answer : The correct option is, 23.6 g

Explanation : Given,

Mass of $Mg_3N_2$ = 100.0 g

Mass of $H_2O$ = 75.0 g

Molar mass of $Mg_3N_2$ = 101 g/mol

Molar mass of $H_2O$ = 18 g/mol

First we have to calculate the moles of $Mg_3N_2$ and $H_2O$ .

$\text{Moles of }Mg_3N_2=\frac{\text{Given mass }Mg_3N_2}{\text{Molar mass }Mg_3N_2}$

$\text{Moles of }Mg_3N_2=\frac{100.0g}{101g/mol}=0.990mol$

and,

$\text{Moles of }H_2O=\frac{\text{Given mass }H_2O}{\text{Molar mass }H_2O}$

$\text{Moles of }H_2O=\frac{75.0g}{18g/mol}=4.17mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$Mg_3N_2(s)+6H_2O(l)\rightarrow 3Mg(OH)_2(aq)+2NH_3(g)$

From the balanced reaction we conclude that

As, 6 moles of $H_2O$ react with 1 mole of $Mg_3N_2$

So, 4.17 moles of $H_2O$ react with $\frac{4.17}{6}=0.695$ moles of $Mg_3N_2$

From this we conclude that, $Mg_3N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2O$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 6 moles of $H_2O$ react to give 2 moles of $NH_3$

So, 4.17 moles of $H_2O$ react to give $\frac{2}{6}\times 4.17=1.39$ mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

Molar mass of $NH_3$ = 17 g/mole

$\text{ Mass of }NH_3=(1.39moles)\times (17g/mole)=23.6g$

Therefore, the maximum theoretical yield of $NH_3$ is, 23.6 grams.

4 0

3 years ago

Hydrogen bonds can be found between molecules of which substance?

Ratling [72]

I believe the answer is D

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3 years ago

To get dna out of a living cell, how many cell membranes would you need to pierce or remove?

Ivenika [448]

DNA extraction from living cell
DNA is present inside nucleus surrounded by nuclear membrane. then cell is surrounded by plasma membrane, it means that DNA inside living cell is enclosed in two layers.

Removal of cell membrane
In order to remove cell membrane some detergents are applied followed by physical lysis through vertex.when the first cell membrane is pierced it is removed through centifugation by adding phenol and chloroform.

Removal of nuclear membrane
Proteinase enzyme is added which help in rupturing of nuclear membrane and removal of histone protein from DNA. Then RNAse is added to remove RNA from DNA.

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3 years ago

Classify the organisms as vascular, nonvascular

blsea [12.9K]

A:vascular B:vascular C:Non-vascular D:Non-vascular

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3 years ago

WHAT HAPPENS WHEN AN ATOM LOSES AN ELECTRON TO ANOTHER ATOM?

cluponka [151]

It will become an ion and no longer be neutral

8 0

4 years ago

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