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2 years ago

Between which two consecutive numbers does the root of 90 lie

Mathematics

1 answer:

dezoksy [38]2 years ago

4 0

Answer:

$9 < \sqrt{90} < 10$

Step-by-step explanation:

Since $9^2=81 < 90$ and $10^2=100 > 90$ , then $9 < \sqrt{90} < 10$

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2 years ago

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Answer:

Step-by-step explanation:

<u>Factoring</u>

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3 years ago

Read 2 more answers

What number is it that, when multiplied by 18,27,36,45,54,63,72,81, or 99, gives a product in which the first and last figures a

allsm [11]

The given multipliers are factors of 9, the possible number will have 1 as first and last digit which gives the number as 101

<h3>How can the correct number be found?</h3>

The given numbers are;

18, 27, 36, 45, 54, 63, 72, 81, 99

Given that the first and the last figures are those of the multipliers, we have;

The first and last and last digit of the number can be 1, which gives;

Possible numbers includes; 11 and 101

By trying the possible numbers, the difference found is presented as follows;

99 × 11 = 1089 (The first and the last digit are not the same as the multiplier)

99 × 101 = 9999 (First and last digit are not the same as the multiplier)

90 × 11 = 990

90 × 101 = 9090

The correct option is therefore 101

The number is 101

Learn more about multiplication of numbers here:

brainly.com/question/83239

#SPJ1

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2 years ago