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Over [174]
3 years ago
7

George wishes to increase the percent of acid in 50 ml of a 15% acid solution in water

Mathematics
2 answers:
PtichkaEL [24]3 years ago
3 0

Answer:

screw this question

Step-by-step explanation:

To change from 15% to 25% he needs to add 10%.

If the solution is 50ml then he needs to add 10% which is 5ml... But if he adds 5 ml then the solution will be 55ml total, so that doesn't make sense. He has to take some of the solution that's not acid before adding the 5ml...

sammy [17]3 years ago
3 0

Answer:

20/3 ml

Step-by-step explanation:

Original solution volume is 50ml out of which 15% is acid

Vol of acid in solution = 15% x 50 = 7.5 ml

Let's add X ml of acid to solution so that acid % is 25%

New acid volume = X + 7.5

New solution volume = X + 50

Using ratio of acid/solution gives us (X+7.5)/(X+50) = 25/100

or,

(X + 7.5)/(X+50) = 1/4

Cross-multiplying

4(X+7.5) = X + 50

4X + 30 = X + 50

3X = 20

X = 20/3  ANS

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No, its not equivalent

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mr_godi [17]

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For the pie chart shown, what is the maximum number of people who could have an income of $45,000 if the total number of people
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3 years ago
Solve for w, where w is a real number.
Ber [7]

Answer:

w= 9

Step-by-step explanation:

\sqrt{ - 4w + 61}  = w - 4

Square both sides:

-4w +61= (w -4)²

\boxed{(a - b)^{2}  = a^2 -2ab + b^2 }

Expand:

-4w +61= w² -2(w)(4) +4²

-4w +61= w² -8w +16

Simplify:

w² -8w +16 +4w -61= 0

w² -4w -45= 0

Factorize:

(w -9)(w +5)= 0

w -9= 0 or w +5= 0

w= 9 or w= -5 (reject)

Note:

-5 is rejected since we are only taking the positive value of the square root here. If the negative square root is taken into consideration, then w= -5 would give us -9 on both sides of the equation.

<u>Why </u><u>do </u><u>we </u><u>use </u><u>negative </u><u>square </u><u>root?</u>

When solving an equation such as x²= 4,

we have to consider than squaring any number removes the negative sign i.e., the result of a squared number is always positive.

In the case of x²= 4, x can be 2 or -2. Thus, whenever we introduce a square root, a '±' must be used.

However, back to our question, we did not introduce the square root so we should not consider the negative square root value.

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