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Over [174]
2 years ago
7

George wishes to increase the percent of acid in 50 ml of a 15% acid solution in water

Mathematics
2 answers:
PtichkaEL [24]2 years ago
3 0

Answer:

screw this question

Step-by-step explanation:

To change from 15% to 25% he needs to add 10%.

If the solution is 50ml then he needs to add 10% which is 5ml... But if he adds 5 ml then the solution will be 55ml total, so that doesn't make sense. He has to take some of the solution that's not acid before adding the 5ml...

sammy [17]2 years ago
3 0

Answer:

20/3 ml

Step-by-step explanation:

Original solution volume is 50ml out of which 15% is acid

Vol of acid in solution = 15% x 50 = 7.5 ml

Let's add X ml of acid to solution so that acid % is 25%

New acid volume = X + 7.5

New solution volume = X + 50

Using ratio of acid/solution gives us (X+7.5)/(X+50) = 25/100

or,

(X + 7.5)/(X+50) = 1/4

Cross-multiplying

4(X+7.5) = X + 50

4X + 30 = X + 50

3X = 20

X = 20/3  ANS

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Lily is a lilypad in a small pond. Lily doubles in size each day. On the 20th day she covers the whole pond. On what day was Lil
svetoff [14.1K]

Answer:

19th day

Step-by-step explanation:

So say Lily was 1 when Lily was planted

First day Lily is 2

Second day Lily is 4

Third day Lily is 8

etc...

See the pattern?

The pattern is 2^x

On the 20th day, Lily was 2^20

So when Lily was half, Lily was 2^20 / 2

2^x = 2^20 / 2

2^x = 2^19

On the 19th day, Lily was half.

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3 years ago
What are the zeros of this graph
kotegsom [21]

The zeroes ( where the graph cuts the x axis) ar (-2,0) AND (2,0)

tHE FACTOrIAL FORM IS (x - 2)(x + 2)

Its B

3 0
4 years ago
I do not have the energy to do this, someone help please?
matrenka [14]
Separate into two groups
y^3(5y+4) + 5(5y+4)
(y^3 + 5)(5y + 4)
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{
il63 [147K]

Answer:

\frac{x-3}{2x-3}. hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

x^2-5x+6

Now let's find what ac is (it's just c since a=1...)

AC= 6

List factors of -6

\pm1, \pm2, \pm3, \pm6.

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

(x-2)(x-3)

Ok now let's factor the second equation:

2x^2-7x+6

Multiply a and c

AC = 12

List factors of 12:

\pm1, \pm2, \pm3, \pm4, \pm6, \pm12.

Factors that add up to -7 and multiply to 12:

-3\ and\ -4

Rewrite equation:

2x^2-4x-3x+6

Group terms:

(2x^2-4x)+(-3x+6)

Factor out GCF:

2x(x-2)-3(x-2)

Rewrite:

(2x-3)(x-2)

Now let's write out the equation using these factors:

\frac{(x-2)(x-3)}{(2x-3)(x-2)}.

Here we can factor out the x-2 and the simplified form is:

\frac{x-3}{2x-3}

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0
2 years ago
In AMNO, m = 41 cm, o = 98 cm and Angle O=22º. Find all possible values of Angle M, to the nearest degree.​
skelet666 [1.2K]

Answer:

Answer:

85t

Step-by-step explanation:

1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

hope this helps

6 0
3 years ago
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