Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
, D
Step-by-step explanation:
3 if x is greater than or equal to 1 is nothing. That leaves us with 
if x<1. If you substitute in 1 for x, you get 3, but of course that isn't possible, so the range is , which is D.
9514 1404 393
Answer:
8
Step-by-step explanation:
Your familiarity with multiplication tables tells you ...
64 = 8·8 = 8²
The missing base is 8.
Collect like terms
-3w - 7 w =5
Divide both sides by -10
-10w =5
w = -1/2
