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grigory [225]
2 years ago
12

HELP ASAP PLSSSSSSSSSS

Mathematics
1 answer:
inysia [295]2 years ago
6 0

Answer:

Neighborhood Q appears to have a bigger family size

Step-by-step explanation:

Mean = the sum of all data values divided by the total number of data values

Number of families in Neighborhood Q = 9

Mean family size of Neighborhood Q:

= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9

= 35 ÷ 9

= 3.888888...

Number of families in Neighborhood S = 9

Mean family size of Neighborhood S:

= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9

= 27 ÷ 9

= 3

The mean family size of Neighborhood Q is 3.88..  and the mean family size of Neighborhood S is 3.  Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.

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wariber [46]
The best way to multiply complicated problems mentally* is to break them into chunks.

Start with 20 times 8 to get 160, and then 8 times 5 to get 40. Add these together to get 200. 200 times 3 is 600, and 20 times 200 is 4000. Add these together to get your final answer, 4600. 

In other words 8 x 20 + 8 x 5 = 200  200 x 3 + 200 x 20 = 4600

*I assumed you meant mentally, because otherwise you'd just multiply longhand, multiplying two of the three numbers and then multiplying their product with the third. 
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4 years ago
Seth's balcony is 7 feet wide and 14 feet long. Seth paid $4.00 per square foot to have the
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3 years ago
what are the minimum first quartile median third quartile and the maximum of the data set? 9,20,4,18,4,18,20,9
den301095 [7]
<u>Answers</u>
1. Minimum = 4
2. First quartile = 6.5
3. Median = 13.5
4. Third quartile = 19
5. Maximum = 20

<u>Explanation</u>
To calculate the measure of central tendency, you first arrange the set of the data in ascending order.  
The set of data given will be;
4, 4, 9, 9, 18, 18, 20, 20.

Part 1:
The minimum value of the data is 4.

Part 2:
The first quatile is the median of the lower half which is comprised by:
4, 4, 9, 9

1st quartile = (4+9)÷2
                  = 13÷2
                  = 6.5

Part 3:
Median of the data is;

Median = (9+18)÷2
              =27÷2
            = 13.5

Part 4:
3rd quartile is the median of the upper half which comprises of; 
18, 18, 20, 20.

3rd quartile = (18+20)÷2
                  = 48÷2
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Part 5
The maximum of the set of data is 20.
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3 years ago
Please someone help me. Im giving brainliest!
Ivahew [28]

10x-45-4x-2

6x- 47= 1

6x=1+47

6x=48

x=8

PLEASE MARK BRAINLIEST

7 0
3 years ago
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$80

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