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amm1812
2 years ago
14

What’s the area and the perimeter and of the triangle?

Mathematics
1 answer:
weeeeeb [17]2 years ago
7 0

Answer:

16.5

Step-by-step explanation:

7.5 x 2.2. formula of triangle = bh

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Which pair of angle measures satisfy the condition sin J = cos K?
kipiarov [429]
Sin J = cos K
sin J = cos (90 - J)

So, K = 90 - J

Therefore, 60 deg, 30 deg satisfy the condition sin J = cos K.
5 0
3 years ago
Find the area of the figure
MakcuM [25]

9514 1404 393

Answer:

  24.885 in²

Step-by-step explanation:

Use the formula for the area of a triangle.

  A = 1/2bh . . . . . . . where b is the base length and h is the height perpendicular to the base

  A = 1/2(7.9 in)(6.3 in) = 24.885 in²

_____

<em>Additional comment</em>

The given side lengths cannot form a triangle, as the side shown as 14.7 is too long for the ends of the other segments to connect to. The attachment shows that side should be 11.97 in.

5 0
2 years ago
What is the axis of symmetry of the parabola? 12(x+3)= (y–2)2a)
Sav [38]

Answer:

a (y - 2)/6-3 is the answer

hope this helped

6 0
2 years ago
Triangle ABC has coordinates A(-2, -3), B(1, 1), and C(2, -1). If the triangle is translated 4 units up, what are the coordinate
DochEvi [55]

Answer:

The coordinates of point A' will be: A'(-2, 0)

Step-by-step explanation:

We know that a translation is basically a transformation that occurs when an object is moved from one place to another place.

Translation does not change the size, orientation, or shape of the original object.

Translating a point P(x, y) 4 units up means we need to add to use P'(x, y+4), that is adding 4 units to the y-coordinate of the point P'(x, y).

Now we have to translate the triangle 4 units up. So, use the formula

P(x, y) → P'(x, y + 3)

Thus, the coordinates of point A' will be:

A(-2, -3) → A'(-2, -3+3) → A'(-2, 0)

Therefore, the coordinates of point A' will be: A'(-2, 0)

8 0
3 years ago
Can someone help me with number 8 please? Thank you.
Naddik [55]
Answer: -4 \le x \le 5
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\}

------------------------------------------------------------------------------

Explanation:

The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.

So that's how I got -4 \le x \le 5 (x is between -4 and 5; inclusive of both endpoints)

Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"

Writing \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\} is the set-builder notation way of expressing the domain. The x\in\mathbb{R} portion means "x is a real number"

6 0
3 years ago
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