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Marizza181 [45]
3 years ago
7

Find the Probability of P(bankrupt)

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0
0.22 because one side is 11 and the other is 11 so 11+11 is 22 the pursent of 22 is 0.22
Cerrena [4.2K]3 years ago
7 0
I agree with the other person
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Let x = 4.<br><br><br><br> What is the value of y in the equation y = 15 + 11 + x?
marishachu [46]
Okay so you have to add up 15 and 11 and 4 so your answer is y=30


5 0
3 years ago
Find the value of x.
Svetach [21]

Answer:

35

Step-by-step explanation:

x + 55 = 90

x = 90 - 55

x = 35

4 0
3 years ago
Read 2 more answers
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Which of the following expressions is this one equivalent to?
schepotkina [342]

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}

Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

Factoring again in the numerator with common factor x^{3}+1:

\frac{(x^{3}+1)(x-2)}{x^{3}+1}

Simplifying:

x-2

Hence, the correct option is C. x-2

3 0
3 years ago
Solve the inequality.
mr Goodwill [35]

Answer:

the first one, v < 1 23/25

Step-by-step explanation:

multiply both sides by 6 and divide by 5

v < 48/25, or v < 1 23/25

5 0
3 years ago
Read 2 more answers
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