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mr_godi [17]
3 years ago
5

HELP ME PLEASE ITS DUE TODAY!!!!

Mathematics
1 answer:
Stells [14]3 years ago
5 0

Step-by-step explanation:

- 5 - ( - 4) =  - 5 + 4 =  - 1 \\  - 4 - ( - 5) =  - 4 + 5 = 1 \\  - 4 - (5) =  - 4 - 5 =  - 9 \\ 4 - ( - 5) = 4 + 5 = 9

Therefore ranking them from least to most:

- 4 - (5) \\  - 5 - ( - 4) \\  - 4 - ( - 5) \\ 4 - ( - 5)

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Consider the following incomplete deposit slip: Description Amount ($) Cash, including coins 150 75 Check 1 564 81 Check 2 2192
ololo11 [35]
Given that following incomplete deposit slip:

<span>Description                    Amount ($)

Cash, including coins     $150.75
Check 1                          $564.81
Check 2                       $2,192.43
Check 3                       $4,864.01

Subtotal                       $7,772.00

Less cash received       ($721.50)

Total                             $7,050.50

Therefore, the amount of cash the person who filled out this deposit slip received is $721.50
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3 0
3 years ago
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Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$
bagirrra123 [75]

Answer:

5\sqrt{3}

Step-by-step explanation:

\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}

All Done!

8 0
3 years ago
Read 2 more answers
find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be
olasank [31]
Hello,

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Answer B (but see the problem)
7 0
3 years ago
Read 2 more answers
Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl
GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3

Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

7 0
3 years ago
Happy snow day! My project
attashe74 [19]

Answer:

21 Snowmen

Step-by-step explanation:

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Each snowman is 5ft across, so divide 106ft by 5ft.

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