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Minchanka [31]
2 years ago
8

s A bag contains 9 red marbles, 6 white marbles, and 7 blue marbles. Randomly choose two marbles, one at a time, and without rep

lacement. Find the following. The probability that the first marble is white and the second is blue
Mathematics
1 answer:
laila [671]2 years ago
3 0
The probability of white is 6/16
The probability of blue is 7/15
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Nevermind, i solved my problem
bezimeni [28]

Answer:

What was the problem?

Step-by-step explanation:

Oh ok , I G u e s s it is solved already.

8 0
3 years ago
If 2x - 3y = 24 and 3x + 4y = 2, what is the value of x - y?
ruslelena [56]

Answer:

10

Step-by-step explanation:

<u><em>y = -4 </em></u>

<u><em>x = 6 </em></u>

<em><u>x-y = 6-(-4) = 6+4 = 10</u></em>

<em><u /></em>

8 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

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P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
Simplify. (-2y^3)^3(-3x^2yz^2)^3
Alik [6]

=-8y^9*-27x^6y^3z^6

=216x^6y^12z^6

6 0
3 years ago
Plz answer will mark brainliest
LUCKY_DIMON [66]

Answer:

(5.5, 6)

Step-by-step explanation:

Find the difference between them and then divide by 2 and add to one point

7 0
3 years ago
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