Question

Help! Please explain I have a test tomorrow !

Answer 1

given:

base= 10 ft

height= 12 ft

to find:

the surface area of the given pyramid.

solution:

$s.a = {a}^{2} + 2a \sqrt{ \frac{ {a}^{2} }{4} + {h}^{2} }$

$s.a = {10}^{2} + 2 \times 10 \times \sqrt{ \frac{ {10}^{2} }{4} { \times 12}^{2} }$

$s.a = 360 \: {ft}^{2}$

therefore, the surface area of the given pyramid is 360 square feets.

answer= option D