Answer:
Therefore, the inverse of given matrix is
Step-by-step explanation:
The inverse of a square matrix 
is 
such that
where I is the identity matrix.
Consider, ![A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%5C%5C3%266%5Cend%7Barray%7D%5Cright%5D)
Therefore, the inverse of given matrix is
False. In order to have an inverse, your function must pass the horizontal line test. The graph fails the test.
For this case what you should do is evaluate values of x in the function and verify that they meet the result of f (x) shown in the graph.
The answer is
f (x) = - 2lxl +1
notice that
f (1) = - 2l1l + 1 = -1
f (-1) = - 2l-1l + 1 = -1
Both comply with the value of f (x) shown in the graph
answer
f (x) = - 2lxl +1
46+19+54= 119, so the answer is 119
Answer:
C AND D
Step-by-step explanation:
AP EX Confirmed
