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marshall27 [118]
3 years ago
11

Please Help! Given parallelogram ABCD with the measures shown, what is the Measure of 5?

Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

m\angle 5=76\degree.

Step-by-step explanation:

In the given parallelogram, line AC is a transversal.

Using the alternate interior angles theorem,

m\angle 5=76\degree.

You can observe this by tracing a Z-pattern.

You will then observe that m<5 and the 76\degree angles are alternate interior angles.

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Which of the following is the conjugate of a complex number with 2 as the real part and −8 as the imaginary part?
vampirchik [111]
The complex number is given as: 2-8i

So for conjugate, you just flip the sign of the imaginary part:

2+8i will be the answer
3 0
3 years ago
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A gift box has the shape of a cube with an edge length of 4.5 in.
DIA [1.3K]

Answer:

4.5 times 4.5 times 4.5 = 91.125

Step-by-step explanation

To find the volume you do v= length times width times height.

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2 years ago
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Photo attached <br><br> A. -2<br> B. -1<br> C. 1/-2<br> D. 1/2
kifflom [539]

Step-by-step explanation:

(X1,Y1) = (-2,2)

(X2,Y2) = (0,1)

• Find slope.

m = (Y2 - Y1)/(X2 - X1)

m = (1 - 2)/(0 - (-2))

m = -1/2

The answer is C.

6 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

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3 years ago
Consider the diagram below.
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Answer:

Is D I think

Step-by-step explanation:

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2 years ago
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