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3 years ago

Find the value of n that makes ΔDEF ∼ΔXYZ when DE = 4, EF = 5, XY = 4(n+1), YZ = 7n - 1, and ∠E ≅∠Y. n =

Mathematics

2 answers:

faust18 [17]3 years ago

4 0

Answer:

answer is 3

Step-by-step explanation:

they are correct

dalvyx [7]3 years ago

3 0

Answer:

Step-by-step explanation:

It's given that ΔDEF ∼ΔXYZ . So the corresponding sides of both triangles will be proportional to each other.

$= > \frac{de}{xy} = \frac{ef}{yz} = \frac{df}{xz}$

DE = 4 ; XY = 4(n + 1) ; EF = 5 ; YZ = 7n - 1

Putting all these values gives ,

$\frac{4}{4(n + 1)} = \frac{5}{7n - 1}$

$= > \frac{1}{n + 1} = \frac{5}{7n - 1}$

$= > 7n - 1 = 5(n + 1)$

$= > 7n - 1 = 5n + 5$

$= > 7n - 5n = 5 + 1$

$= > 2n = 6$

$= > n = \frac{6}{2} = 3$

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Please give a good answer :)

Alex

Answer:

P(4≤x≤7) = 2/3

Step-by-step explanation:

We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Adding the outcome together, the sample space (S) becomes:

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

Next, we shall obtain the event of 4≤x≤7. This is illustrated below:

4 5 6 7

Finally, we shall determine P(4≤x≤7). This can be obtained as follow:

Element in the sample space, n(S) = 36

Element in 4≤x≤7, n(4≤x≤7) = 24

Probability of 4≤x≤7, P(4≤x≤7) = ?

P(4≤x≤7) = n(4≤x≤7) / nS

P(4≤x≤7) = 24/36

P(4≤x≤7) = 2/3

4 0

3 years ago

What is the slope- intercept equation of the line that passes through(0,2) and (6,6)?

Vsevolod [243]

Answer:

y = 2/3x +2

Step-by-step explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

= (6-2)/(6-0)

=4/6

=2/3

The slope intercept form of the equation for a line is

y= mx+b

y =2/3 x +b

We know the y intercept is 2 (the y intercept is when x=0)

y = 2/3x +2

7 0

3 years ago

Read 2 more answers

Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long

7nadin3 [17]

The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:
$k = \frac{RP}{HF}$
$k = \frac{7.2}{12}$
$k = 0.6$
To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:

For PQ
$PQ = k * FG

PQ = 0.6 * 5

PQ = 3$

For QR
$QR = k * GH

QR = 0.6 * 10

QR = 6$

Answer:
You have that the lengths for the other two sides of triangle PQR are:
$PQ = 3

QR = 6$