Answer:
4.2
Step-by-step explanation:
4.1553
15 -> 2
4.2
Answer:
2x^3−7x^2+16x−15
Step-by-step explanation:
(2x−3)(x^2−2x+5)
=(2x+−3)(x^2+−2x+5)
=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)
=2x^3−4x^2+10x−3x^2+6x−15
=2x3−7x2+16x−15
7/8 x = 21
7x = 21×8
7x = 168
x = 24
Answer:
Step-by-step explanation:
First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items
F(x) = x^3-3x^2+0x+0
We have to divide this by x-2
Leading terms in the dividend and divisor are
x^3 and x
Hence quotient I term would be x^3/x=x^2
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
Multiply x-2 by x square and write below the term and subtract
We get
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
---------------
-x^2+0x
Again take the leading terms and find quotient is –x
x-2) x^3-3x^2+0x+0(x^2-x
x^3-2x^2
---------------
-x^2+0x
-x^2-2x
Subtract to get 2x +0 as remainder.
x-2) x^3-3x^2+0x+0(x^2-x-2
x^3-2x^2
---------------
-x^2+0x
-x^2+2x
-------------
-2x-0
-2x+4
------------------
-4
Thus remainder is -4 and quotient is x^2-x-2
