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dolphi86 [110]
4 years ago
7

Provide conditions under which the mean function is linear but has a negative coefficient

Mathematics
1 answer:
den301095 [7]4 years ago
5 0
Depending on your dependent/outcome variable, a negative value for your constant/intercept should not be a cause for concern. This simply means that the expected value on your dependent variable will be less than 0 when all independent/predictor variables are set to 0. For some dependent variables, this would be expected. For example, if the mean value of your dependent variable is negative, it would be no surprise whatsoever that the constant is negative; in fact, if you got a positive value for the constant in this situation, it might be cause for concern (depending on your independent variables).Even if your dependent variable is typically/always positive (i.e., has a positive mean value), it wouldn't necessarily be surprising to have a negative constant. For example, consider an independent variable that has a strongly positive relationship to a dependent variable. The values of the dependent variable are positive and have a range from 1-5, and the values of the independent variable are positive and have a range from 100-110. In this case, it would not be surprising if the regression line crossed the x-axis somewhere between x=0 and x=100 (i.e., from the first quadrant to the fourth quadrant), which would result in a negative value for the constant.The bottom line is that you need to have a good sense of your model and the variables within it, and a negative value on the constant should not generally be a cause for concern. Typically, it is the overall relationships between the variables that will be of the most importance in a linear regression model, not the value of the constant.
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What would make the bottom = 0
Minchanka [31]
So you need x^5 - 81x = 0
x^5 - 81x = 0
Divide both sides by x
x^4 -81 = 0
Add both sides by 81
x^4 = 81
Take the 4th root of both sides
x = 3

That's your answer.

x = 0 would also work, which is another possible answer.

Have an awesome day! 

From your friendly Helper-in-Training, collinjun0827

P.S. Instead of saying "bottom", say "denominator"
6 0
3 years ago
Find the line passing thru (-2,-3) and (4,0) . Write it's equation
Scorpion4ik [409]
The y intercept i think
6 0
4 years ago
Read 2 more answers
K here’s another one please help
Luden [163]

Answer:

Both the relations are functions, the correct answer is a.

Step-by-step explanation:

In order to solve this problem we will first find the inverse relation as shown below:

y = 3x^2 + 5\\x = 3y^2 + 5\\3y^2 = x - 5\\y^2 = \frac{x - 5}{3}\\y = \sqrt{\frac{x - 5}{3}} = \frac{\sqrt{x - 5}}{\sqrt{3}}\\y = \frac{\sqrt{x - 5}\sqrt{3}}{\sqrt{3}\sqrt{3}} = \frac{\sqrt{3x - 15}}{3}

Functions are relations between two groups of numbers, for which the input must generate only one output. Using this definition we can classify both the relation and its inverse as a function, therefore the correct answer is a.

7 0
4 years ago
a cone and a sphere have the same volume. the height of the cone is 96 units. what would be the values for the radius of the con
jolli1 [7]

The volume V_c of a cone  with base radius r_c and height h_c is

V_c = \dfrac{1}{3}\pi r_c^2 h_c

Similarly, the volume V_s of a sphere with radius r_s is

V_s = \dfrac{4}{3}\pi r_s^3

We know that V_c=V_s and that h_c=96

So, we can set up the following equation:

\dfrac{96}{3}\pi r_c^2=\dfrac{4}{3}\pi r_s^3

We can simplify the common denominator 3, and pi appearing on both sides:

96r_c^2=4r_s^3

We can divide both sides by 4:

24r_c^2=r_s^3

Without further information, this is all we can say: the cubed radius of the sphere is the same as 24 times the squared radius of the cone.

3 0
4 years ago
A student number system for a county requires that the student number be 5
Damm [24]

Answer:

B

Step-by-step explanation:

First Character: 21 consonant

2nd 3rd and 4th: 10* 9* 8 = 720

Last Character: 26

Total Ways 21 * 720 * 26 = 393120

6 0
3 years ago
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