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grandymaker [24]
2 years ago
15

In a class of 23,there are 13 girls and 10 pupils who play chess .The number of girls play chess is 4.Find how many boys do not

play chess. Topic :word problems involving set.Note:solve it by formula method and not venn diagram.Ur work should be shown clearly.30 points. A need it hurry​
Mathematics
2 answers:
dimaraw [331]2 years ago
6 0
Answer:
4, have a good day
sineoko [7]2 years ago
4 0

Answer: 4

Step-by-step explanation:

If there are 13 girls in a class of 23, we can assume there are 10 boys. If 4 girls play chess and there are 10 pupils who play chess, we can guess that the remaining 6 are boys. If there are 10 boys, and 6 of them play chess, there are 4 who do not.

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The increasing annual cost (including tuition, room, board, books, and fees) to attend college has been widely discussed (Time).
NeX [460]

Answer:

(a) PRIVATE COLLEGES

Sample mean is $42.5 thousand

Sample standard deviation is $6.65 thousand

PUBLIC COLLEGES

Sample mean is $22.3 thousand

Sample standard deviation is $4.34 thousand

(b) Point estimate is $20.2 thousand. The mean annual cost to attend private colleges ($42.5 thousand) is more than the mean annual cost to attend public colleges ($22.3 thousand)

(c) 95% confidence interval of the difference between the mean annual cost of attending private and public colleges is $19.2 thousand to $21.2 thousand

Step-by-step explanation:

(a) PRIVATE COLLEGES

Sample mean = Total cost ÷ number of colleges = (51.8+42.2+45+34.3+44+29.6+46.8+36.8+51.5+43) ÷ 10 = 425 ÷ 10 = $42.5 thousand

Sample standard deviation = sqrt[summation (cost - sample mean)^2 ÷ number of colleges] = sqrt([(51.8-42.5)^2 + (42.2-42.5)^2 + (45-42.5)^2 + (34.3-42.5)^2 + (44-42.5)^2 + (29.6-42.5)^2 + (36.8-42.5)^2 + (51.5-42.5)^2 + (43-42.5)^2] ÷ 10) = sqrt (44.24) = $6.65 thousand

PUBLIC COLLEGES

Sample mean = (20.3+22+28.2+15.6+24.1+28.5+22.8+25.8+18.5+25.6+14.4+21.8) ÷ 12 = 267.6 ÷ 12 = $22.3 thousand

Sample standard deviation = sqrt([(20.3-22.3)^2 + (22-22.3)^2 + (28.2-22.3)^2 + (15.6-22.3)^2 + (24.1-22.3)^2 + (28.5-22.3)^2 + (22.8-22.3)^2 + (25.8-22.3)^2 + (18.5-22.3)^2 + (25.6-22.3)^2 + (14.4-22.3)^2 + (21.8-22.3)^2] ÷ 12) = sqrt (18.83) = $4.34 thousand

(b) Point estimate = mean annual cost of attending private colleges - mean annual cost of attending public colleges = $42.5 thousand - $22.3 thousand = $20.2 thousand.

This implies the the mean annual cost of attending private colleges is greater than the mean annual cost of attending public colleges

(c) Confidence Interval = Mean + or - Margin of error (E)

E = t×sd/√n

Mean = $42.5 - $22.3 = $20.2 thousand

sd = $6.65 - $4.34 = $2.31 thousand

n = 10+12 = 22

degree of freedom = 22-2 = 20

t-value corresponding to 20 degrees of freedom and 95% confidence level is 2.086

E = 2.086×$2.31/√22 = $1.0 thousand

Lower bound = Mean - E = $20.2 thousand - $1.0 thousand = $19.2 thousand

Upper bound = Mean + E = $20.2 thousand + $1.0 thousand = $21.2 thousand

95% confidence interval is $19.2 thousand to $21.2 thousand

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3 years ago
3. What is an equation of the line through (4, 2)
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The answer is c.......
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3 years ago
5 is to 7 as is to 49
Ostrovityanka [42]
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3 0
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Determina si 2018 es un termino de la siguiente progresion aritmetica 17,46,75,104,133,....
Kitty [74]
2018 is the 70th term of the progression.

Explanation
We start out finding the common difference of the progression:
46-17 = 29

Now we write the explicit formula for the sequence.  It is of the form
a_n=a_1+d(n-1)
\\
a_n=17+29(n-1)

We set this equal to 2018 to see if the answer is a whole number.  If it is, it will be the term number that gives us 2018:

2018=17+29(n-1)

Using the distributive property,
2018=17+29*n-29*1
2018=17+29n-29

Combine like terms:
2018=29n-12

Add 12 to both sides:
2018+12=29n-12+12
2030=29n

Divide both sides by 29:
2030/29=29n/29
70=n

Since n=70, this means 2018 is the 70th term of the sequence.
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mario62 [17]

Answer:

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Step-by-step explanation:

B is 4 units to the left of the origin.

6 0
2 years ago
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