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krok68 [10]
3 years ago
15

If EF = 2x+13, FG = 20, and EG = 71 what's the value of x​

Mathematics
1 answer:
klemol [59]3 years ago
6 0

Answer:

<h2>x = 19</h2><h2></h2>

Step-by-step explanation:

|<----------------- 71 ----------------------->|

E-----------------------F---------------------G

       2x + 13                 20

find: x

EF + FG = DG

2x + 13 + 20 = 71

2x = 71 - 20 - 13

x = 38 / 2

x = 19

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Which of the following sets of ordered pairs is a function?
Ulleksa [173]

Answer:

(1,5) (2,6) (3,7) (4,8)

8 0
3 years ago
The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?
Scilla [17]

Given

The figure is rotated 360° clockwise with the origin as the center of rotation. Which graph represents the rotated figure?

Answer

After the rotation of 360 degrees, a figure comes back to original position

Option A is correct

4 0
1 year ago
Find the vertical asymptotes. 2x2 + 7x + 6 y = 3x2 + 10x - 8 * = [ [?], x=​
Llana [10]

Answer:

-\frac{77}{24}

Step-by-step explanation:

1. rewrite the equation in standard form: 4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2

2. find (h,k), the vertex. the vertex is \left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a  distance p from the \left(-\frac{3}{2},\:-\frac{41}{24}\right) y coordinate which is at  -\frac{41}{24}\right). Set up the equation:

y=-\frac{41}{24}-p

5. substitute and solve:

y=-\frac{41}{24}-\frac{3}{2}

y = -\frac{77}{24}

hope this helps, ask me questions if you still don't understand.

8 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)
Liono4ka [1.6K]

Answer:

<h2>3.6°</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

u*v = |u||v| cos \theta

\theta is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

5 0
3 years ago
Write the polar coordinates (3, pi) in rectangular form. a. (0, 3) c. (-3, 0) b. (3, 0) d. (0, -3)
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In rectangular form, we have the coordinates (3\cos\pi,3\sin\pi)=(3\cdot -1,3\cdot 0)=\boxed{(-3,0)}.

3 0
3 years ago
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