Part (a)
P(A) = 0.5
P(B) = 0.4
P(B/A) = 0.6
P(A and B) = P(A)*P(B/A)
P(A and B) = 0.5*0.6
P(A and B) = 0.3
<h3>Answer: 0.3</h3>
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Part (b)
We'll use the result from part (a)
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.5 + 0.4 - 0.3
P(A or B) = 0.6
<h3>Answer: 0.6</h3>
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Part (c)
A and B are not independent since P(B) does not equal P(B/A). The fact that event A happens changes the probability P(B). Recall that P(B/A) means "probability P(B) based on event A already happened". A and B are independent if P(B) = P(B/A).
Events A and B are not mutually exclusive since P(A or B) is not zero.
<h3>Answer: Neither</h3>
First let's define variables:
r: reading
s: skimming
We write the system of equations that adapts to the problem:
r + s = 275
(15/10) r + (10/15) s = 355
We solve the system of equations:
r = 206
s = 69
Note: see attached image for system solution.
Answer:
Jayden had to skim 69 pages through
Answer:
SHAMALAMAMOOMOO :) :) :) :) :)
your answer is -1/100 (a fraction)
Answer:
n= 250
Step-by-step explanation:
simplify both sides of the equation then isolate the variable