15 POINTS!!!1 HELPPP!!!!!!

the perimeter of a square is equal to the perimeter of an equilateral triangle the length of a side of the square is given by th

diamong [38]

Answer:

x = 3

Step-by-step explanation:

We are told that the length of a side of the square is x.

Now, perimeter of square = 4 × side length

Perimeter of square = 4x

Also,we are told that the triangle is equilateral and a side is (x + 1).

Thus, perimeter of triangle = 3(x + 1)

Since we are told that the perimeter of the square is equal to that of the equilateral triangle. Thus;

4x = 3(x + 1)

4x = 3x + 3

Subtract 3x from both sides to get;

4x - 3x = 3

x = 3

5 0

3 years ago

If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$