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Naddika [18.5K]
2 years ago
12

Can someone show me the steps to this equation.

Mathematics
2 answers:
NeTakaya2 years ago
8 0
z-4\frac{2}{3}=2\frac{2}{3}\ \ \ \ |add\ 4\frac{2}{3}\ to\ both\ sides\\\\z=2\frac{2}{3}+4\frac{2}{3}\\\\z=6\frac{4}{3}\\\\\boxed{z=7\frac{1}{3}}
Crank2 years ago
6 0
So z-4 2/3=2 2/3
so 4 2/3=12/3+2/3=14/3
2 2/3=6/3+2/3=8/3
z-14/3=8/3
multiply both sides by 3
3z-14=8
add 14 to both sides
3z=22
divide both sides by 3
z=22/3=7 1/3

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Okay I don't understand how do I do this. It say :
Lilit [14]

2x+3=17

subtract 3 from each side

2x+3 -3 = 17 -3

2x = 14

divide by 2 on each side

2x/2 = 14/2

x = 7

6 0
3 years ago
Read 2 more answers
Factor the expression 49b²-36​
Travka [436]

Answer:

49b² - 36

Step-by-step explanation:

Find the factors of 49 & 36:

49 = 1, 7, 49

36 = 1, 2, 6, 18, 36

As you can tell, there are no common factors (1 does not count), therefore, the expression given is already in most factored form.

49b² - 36 is your answer.

~

7 0
2 years ago
- 9 (K - 17 ) = 54 please solve​
kirza4 [7]

Answer: k=11

Step-by-step explanation:

7 0
2 years ago
Please can you help me out on this question posted picture
mixer [17]
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)

Thus there are 11 total possible outcomes.

Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)

This means there are 7 outcomes with sum greater than or equal to 9. 

Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11

So, option A gives the correct answer
6 0
3 years ago
PLZZZ HELP ASAP!!!!!!!!!!!!!!!!It is a 75 mile trip to your grandparent's house. Which divisibility rule proves that 75 is an od
TEA [102]

Divisibility by 2 would be the correct answer. Two is an even number, and the only listed at that. Odd numbers are only divisible by another odd number. Hope I helped you !

6 0
3 years ago
Read 2 more answers
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