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Sladkaya [172]
2 years ago
10

“the product of 6 and 9 decreased by 8"

Mathematics
1 answer:
Komok [63]2 years ago
5 0

Answer:

46

Step-by-step explanation:

“the product of 6 and 9 decreased by 8"

“the product of 6 and 9" = 6 * 9

"decreased by 8" = - 8 (subtract 8 from whatever, in this case 6 * 9)

“the product of 6 and 9 decreased by 8" = 6 * 9 - 8 = 46

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Eddi Din [679]

Answer:

625

Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
Find the area of the circle and the sector.
Georgia [21]

Area of a circle is PI x r^2:

Area of circle = 3.14 x 13^2 = 530.66 square meters.

To find the area of the sector multiply the area of the circle by the fraction of the sector

Area of sector = 530.66 x 150/360 = 221.108 square meters ( Round the answer as needed).

6 0
3 years ago
Gcf and lcm of 6 and 9
nadya68 [22]

the lcm is 18

the gcf is 3

3 0
3 years ago
3) Valerie works at a local amusement park. She earns $9.80 per hour. She 20 points
NemiM [27]
<h3>Answer:  Choice A</h3><h3>9.80h+10 = 88.40</h3>

===========================================================

Work Shown:

  • h = number of hours worked.
  • 9.80h = amount of money earned after working h number of hours (ignoring the meal bonus).
  • 9.80h+10 = total amount of money earned after adding on the meal bonus.
  • 9.80h+10 = 88.40 is the equation we use since the total 9.80h+10 is the same as the total she earned 88.40 dollars.

--------------------

Extra info (optional section)

If you want to solve for h, then you could follow these steps.

9.80h+10 = 88.40

9.80h = 88.40-10 ... subtract 10 from both sides

9.80h = 78.40

h = 78.40/9.80 .... divide both sides by 9.80

h = 8

Valerie worked 8 hours on Friday.

As a check,

9.80h + 10 = 88.40

9.80*8 + 10 = 88.40

78.40 + 10 = 88.40

88.40 = 88.40

The answer is confirmed.

3 0
3 years ago
Solve the equation for x<br> -2x = -32
grandymaker [24]

Answer:X=16

Step-by-step explanation:

first you divide -2 ,to -2x and also divide -32 by -2 and you get x=16

Hope this helped!!!

6 0
3 years ago
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