So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!
Answer:
1
Step-by-step explanation:
Step-by-step explanation:
2 consecutive integers : x and x + 1
x + x + 1 = 183
2x + 1 = 183
2x = 183 - 1
2x = 182
x = 182/2
x = 91
x + 1 = 91 + 1 = 92
ur 2 numbers are 91 and 92 with 91 being the smallest integer
