The customer gave you:-- $100-- $5 winning ticket-- $2 winning ticketTotal . . . $107
You gave the customer:-- $17.01 in the form of gas-- $5 in the form of a $5 lottery ticket-- $2 in the form of two $1 lottery tickets-- $3 in the form of a $3 lottery ticketTotal . . . $27.01
In order to be even, you must give the customer another
($107 - $27.01) = $79.99 in change
1/4 or 25 percent because there is a 1/2 chance to get a boy or girl so the probability that will be boys us 1/2 x 1/2= 1/4
Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!
I tried my best with 1, 2, and 3
First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
